Calculation of Materials
Calculation of Materials
a) For 1 m 3 of concrete Mix 1:2:4 (M15)Add 50% for wet concrete = 1.50 m3
= 1.50/(1+2+4) = 0.214 m 3
For 1 m 3 = 30 bags of cement required (1440/50) say 30 bags
Cement = 0.214 x 30 = 6.42 bags
Sand = 0.214 x 2 = 0.428 m 3
Aggregate = 0.214 x 4 = 0.856 m 3
b) Wall plastering in CM 1:4 of 12 mm thick for 100 m 2 :-
Volume = 100 x (12/1000) = 1.20 m 3
Add 30 to 35% as bulking of sand = 0.36 m 3
Add 20 as wastage of sand = 0.312 m 3
Total = 1.872 m 3
= (1.872/1+4) = 0.374 m 3
Cement = 0.374 x 30 = 10.77 bags
Sand = 0.374 x 4 = 1.496 m 3
c) For 100 m 3 of solid Block masonry in CM 1:6 mix 8” thick:-
Volume = 100 x 0.2 (Thickness of wall)
= 20 m 3
No. of blocks required = 20/(0.4 x 0.2 x 0.2)
= 12502 No’s
Volume of mortar = 20-{0.39 x 0.19 x 0.19 x 1250}
= 20 – 17.598
= 2.40 m 3
Note: 200mm – 10 mm for mortar thickness = 190 mm
Blocks =17.598/(0.4 x 0.2 x 0.2)
=1100 No’s
Add 2% wastage = 22
Total = 1122 No’s
Increase by 25% for dry mortar = 3 M 3
= 3/ (1+6)
= 0.429 M 3
Cement = 0.429 x 30 = 12.50 bags
Sand = 0.429 x 6 = 2.57 M 3
Blocks =1122 No’s
STEEL:-
Weight of rod per meter length = d 2 / 162 where d in mm
“L” for column main rod in footing is minimum of 300mm
Hook for stirrups is 9D for one side
For Cantilever anchorage length for main steel is 69D
No. of stirrups = (clear span/Spanning) + 1
Design strength is M 40, target strength is 1.25 x 40 = 50 Mpa
TRAPEZOIDAL FOOTING FORMULA:-
Volume, V = (L x B x D) = H/3{A1 + A2 + sq.rt (A1+A2)}
Where A1 = L x B
A2 = l x b B
H = D-d (Overall depth of footing – depth of
Rectangular footing)
THEROTICAL WEIGHT:-
Cement = 1440 Kg/m 3
Steel = 7850 Kg/m 3
Bricks = 1600 – 1920 Kg/m 3
1 HP = 745.7 watts
WEIGHT OF ROD PER METER LENGTH:-
DIA WEIGHT PER METER
6mm = 0.222
8mm = 0.395
10mm = 0.616
12mm = 0.888
16mm = 1.578
20mm = 2.466
25mm = 3.853
32mm = 6.313
40mm = 9.865
CMENT REQUIREMENTS:-
M10 : 210 Kg
M20 : 320 Kg
M25 : 340 Kg
M30 : 380 Kg
M35 : 410 Kg
M40 : 430 Kg
M45 : 450 Kg
M50 : 450 + M.S 7.5%
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